Correct option (b) R0
Explanation:
For λ/4 line, zin1 = z20/zL = R20/R0/2 = 2R0
For λ/2 line, zL2 = 2R0
For λ/8 line, zL = (2R0)|| 2R0
= R0
For transmission line of length l, zin = z0[(zL + jz0tanβl)/(z0 + jzLtanβl)]
l = λ/8, zin = z0[(zL + jz0)/(z0 + jzL)]
zin = R0[(R0 + jR0)/(R0 + jR0)] = R0