+2 votes
in JEE by kratos

An object, moving with a speed of 6.25 m/*, is decelerated at a rate given by: dv/dt = - 2.5√v where v is the instantaneous speed. The time taken by the object, to come to rest, would be

(a) 2 *

(b) 4 *

(c) 8 *

(d) 1 *

1 Answer

+4 votes
by kratos
 
Best answer

Correct option (a) 2s

Explanation:

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