+1 vote
in JEE by kratos

If ω is a complex cube root of unity, then the value of a + bω + cω2/c + aω + bω2 + a + bω + cω2/b + cω + aω2 is equal to

(a) –1

(b) 2

(c) 2ω

(d) of these

1 Answer

+1 vote
by kratos
 
Best answer

Correct option (a) –1

Explanation:

1/ω (a + bω2 + cω3)/aω + aω2 + c + 1/ω2 (aω2 + bω3+ cω4)/b + cω + aω2

= 1/ω + 1/ω2

ω2 + ω = -1

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