Login

Login
Register

Questions
Unanswered
Tags
Categories
Ask a Question

Find the value of 2^log35 - 5^log32u200bu200bu200bu200bu200bu200bu200b.

+3 votes

asked Feb 26, 2019 in JEE by kratos

Find the value of 2log35 - 5log32.

class-9
jee
jee mains
logarithms

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

+4 votes

answered Apr 22, 2020 by kratos

Best answer

2log35 - 5log32 = 2log2 5 log32- 5log32

= (2log25) - 5log32 = 5log32- 5log32=0

Please log in or register to add a comment.

No related questions found

Snow Theme by Q2A Market

Powered by Question2Answer

Copyright © QinStar.in

...