Or x = 1/2 (x2 − x1 ). In this case, x = 1/2 (378 − 122) = 128 m
Since x1 turns out to be negative, point A **** on the same side of O as B (Fig.). Distance of mid-point P from O is x = (425 + 25) = 225 m. Hence, height of P above O is
Hence, P is (50.2−14) = 36.2 m below point B. It means that mid-point P is (100 − 36.2) = 63.8 m above water level.