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If a = log^2412, b = log^3624, c = log^4836, show that 1 + abc = 2bc.

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in JEE by kratos

If a = log2412, b = log3624, c = log4836, show that 1 + abc = 2bc.

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+1 vote
by kratos
 
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1+abc= 1+ log2aa log3a2a log4a3a= log4a4a+log4aa

=log48(48*12)=log48(24)2=2log4824=2log3624log4836=2bc.

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