Find that number which when successively divided by 7, 5 and 4 leaves remainder 1, 2, 3 respectively the lest quotiant being the sum of the remainders
a) 900
b) 950
c) 960
d) 970
Correct option: (c) 960
Explanation:
Let the number be 'Z'
X = 4 x 6 + 3 = 27
Y = 5x + 2 = 5 (27) + 2 = 137
Z = 7Y + 1 = 7 (137) + 1 = 960