A compound on analysis gave the following percentage composition: Na=14.31% = 9.97%, H = 6.22%, O = 69.5%, calcualte the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, = 32, H = 1, 0 = 16].
Calculation of empirical formula
The empirical formula is Na2 SH20O14
Calculation of Molecular formula
Empirical formula mass = (23 x 2) + 32 + (20 x 1) + (16 x 14)
= 322
Hence molecular formula = Na2 SH20 O14
