Question

Calculate the Miller indices of crystal planes which cut through the crystal axes at (i) (2a, 3b, c) (ii) (a, b, c) (iii) (6a, 3b, 3c) and (iv) (2a, -3b, -3c).

Answer 1

following the procedure given above, we prepare the tables as follows:

| (i) a | b | c | |
| 2 | 3 | 1 | intercepts |
| | 1/3 | 1 | reciprocals |
| 3 | 2 | 6 | clear fractions |
| Hence, the Miller indices are (326). |

| (ii) a | b | c | |
| 1 | 1 | 1 | intercepts |
| 1 | 1 | 1 | reciprocals |
| 1 | 1 | 1 | clear fractions |
| Hence, the Miller indices are (111) |

| (iii) a | b | c | |
| 6 | 3 | 3 | intercepts |
| 1/6 | 1/3 | 1/3 | reciprocals |
| 1 | 2 | 2 | clear fractions |
| Hence, the Miller indices are (122). |

Note: The negative sign in the Miller indices is indicated by placing a bar on the integer. The Miller indices are enclosed within parentheses.