If (2.3)x = (0.23)y = 1000, show that 1/x - 1/y = 1/3
(2.3)x = (0.23)y = 1000
=> log10(2.3)x = log10(0.23)y = log10(103)
=> x log10(2.3) = ylog10(0.23) = 3
=> 3/x = log10 2.3, 3/y = log10 0.23
=> 3(1/x - 1/y) = 1
=> 1/x - 1/y = 1/3