Given : N = 1800 r.p.m. or ω = 2π x 1800/60 = 1888.52 rad/*; r = 50 mm = 0.05 m; l = 200mm; D = 80 mm; mR = 1 kg; P = 0.7 N/mm2; x = 10 mm
1. Net load on the gudgeon pin,
We know that load on the piston,
When the piston has moved 10 mm from the inner **** centre, i.e when P1P = 10 mm, the crank rotates from OC1 to OC through an angle θ
By measurement, we find that θ = 33°.
We know that ratio of legths of connecting rod and crank,
n = l/r = 200/50 = 4
and inertia force on the reciprocating parts,
We know that net load on the gudgeon pin,
FP = FL- F = 3520 - 1671 = 1849 N
2. Thrust in the connecting rod
We know that thrust in the connecting rod,
3. Reaction between the piston and cylinder
We know that reaction between the piston and cylinder,
4. Engine speed at which the above values will become zero
A little consideration will show that the above values will become zero, if inertia force on the reciprocating parts (F1) is equal to the load on the piston (FL). Let ω1 be the speed in rad/*, at which FI = FL