Given Fc = 2000r – 76, m = 5 kg, r1 = 0.1 m, r2 = 0.175 m, F = 5 N.
(i) Maximum and Minimum speeds of equilibrium without considering friction:
Let N2 and N1 be maximum and minimum speeds of the equilibrium respectively.
The controlling force is given by the expression, Fc = 2000r – 76
Controlling force at the minimum radius of rotation (i.e. at r1= 0.1 m)
Fc1 = 2000 x 0.1 – 76 = 124 N
Controlling force at the maximum radius of rotation (i.e. at r2= 0.175 m)
Fc2 = 2000 x 0.175 – 76 = 274 N
(ii) Maximum and Minimum speeds of equilibrium with considering friction: Let N1’ and N1’’ be minimum and maximum speeds of the governor considering friction at minimum radius of rotation. Frictional force at each ball FB = 5 N
Let N1’ and N1’’ be minimum and maximum speeds of the governor considering friction at minimum radius of rotation.
(iii) Co-efficient of Insensitiveness:
w.k.t Co-efficient of sensitiveness at minimum radius of rotation
Co-efficient of sensitiveness at maximum radius of rotation