+3 votes
in Mathematics by kratos

For a series R.L.C circuit the inductor is variable. Source voltage is 200√2sin100πt. Maximum current obtainable by varying the inductance is 0.314 A and the voltage across the capacitor then is 300 V. Find the circuit element values

1 Answer

+3 votes
by kratos
 
Best answer

Under resonant conditions, Im = V/R and VL = VC.

∴ R = V/Im = 200/0.314 = 637 Ω, VC = Im × XCD = Im/ω0 C

∴ C = Im/ω0 VC = 0.314/100π × 300 = 3.33 μF.

VL = Im × XL = Im ω0 L; L = V1/ω0

Im = 300/100 π × 0.314 = 3.03 H

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