By hypothesis
a + b + c = 6
ab + bc + ca= 11
and abc = 6
Therefore
ab + bc + ca /3 = 11/3
and
1/3 (1/ab + 1/bc + 1/ca) = a + b + c/2abc = 6/3 x 6 = 1/3
Hence, the centroid of the triangle is
Caution: First, we have to check whether a, b, c are real or not. In the present case, the roots of the given equation are 1, 2 and 3.