+2 votes
in Chemistry by kratos

What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?

1 Answer

+4 votes
by kratos
 
Best answer

Energy (E) of a photon = hc/λ

Where,λ = wavelength of light = 4000 pm = 4000 x 10-12 m = 4 x 10-9 m

c = velocity of light in vacuum = 3 × 108 m/*

h = Planck’* constant = 6.626 × 10-34 Js

therefore the energy of photon (E) = 6.626 × 10-34 Js X 3 x 108 m/* / 4 x 10-9 m

= 4.965 x 10-16 J

Now 4.965 x 10-16 J is the energy of = 1 photon

Therefore 1 J will be the energy of = 1/4.965 x 10-16 J = 2.014 x 1015 photons

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