If |(x + 1, x - 1), (x - 3, x + 2)| = |(4, -1), (1, 3)|, then write the value of x.
Given that
⇒ (x +1) (x + 2) – (x – 1)(x – 3) = 12 +1
⇒ x2 + 2x + x + 2 – x2 + 3x + x – 3 = 13
⇒ 7x – 1 = 13
⇒ 7x = 14
⇒ x = 2