+3 votes
in Mathematics by kratos

How do you evaluate mechanical work in different steady flow process?

1 Answer

+3 votes
by kratos
 
Best answer

work done by a steady flow process,

and work done in a non–flow process,

1. Constant Volume Process; W1-2 = V(P1 – P2

Steady flow equation

dq = du = dh + d (ke) + d (pv)

Now h = a + pr

Differentiating

dh = du + dtper

= du = pdv = vdp

From First Law of Thermodynamics for a closed system.

2. Constant Pressure process; W1-2 = V(P1 – P2) = 0

3. Constant temperature process;

4. Adiabatic Process; W1-2 = y(P1V1 – P2V2)/(y – 1)

5. Polytropic process; W1-2 = n(P1V1 – P2V2)/( n – 1)

Non – Flow Process

6. Throttling Process The expansion of a gas through an orifice or partly opened valve is called throttling.

The throttling process is a constant enthalpy process. If the readings of pressure and temperature of Joule Thompson porous plug experiment are ploted,

h1 = h2 = h3 = h4 = h

The slope of this constant enthalpy curve is called Joule Thompson coefficient.

For a perfect gas, p = 0.

...