+1 vote
in Mathematics by kratos

Define entropy and show that it is a property of system.

1 Answer

+3 votes
by kratos
 
Best answer

Entropy is a thermodynamics property of a system which can be defined as the amount of heat contained in a substance and its interaction between two state in a process. Entropy increase with addition of heat and decrease when heat is removed.

dQ = T.dS; T = Absolute Temperature and dS = Change in entropy.

dS = dQ/ T

*T- Diagrams**

The area under T-* diagram represent the heat added or rejected. Entropy is a point function From first las

dQ = dU + dW

T.dS = dU + P.dV

Carnot efficiency η = (T1– T2)/T1 = dW/dQ

dW = η.dQ; If T1 – T2 = 1; η =1/T

dW = dQ/T = dS;

if Temperature difference is one.

dS represents maximum amount of work obtainable per degree in temperature.

Unit of Entropy = KJ/K

Principle of Entropy

From claucius inequality

∮ dQ T/ 0

Since dS = dQ/T for reversible process and dS > dQ/T for irreversible process

∮dQ T/ ≤ ∮ dS; or dQ/T d ≤ dS or dS e ≥ dQ/T

Change in Entropy During Process

1. V = C PROCESS

dQ = mCVdT

or, dQ/T = mCVdT/T

dS = mCVdT/T; or S2 – S1 = mCV ln P2/P1

2. P = C; PROCESS

dQ = mCPdT

or, dQ/T = mCPdT/T

dS = mCPdT/T; or S2 – S1 = mCP lnT2/T1 = mCP ln V2/V1

3. T = C; PROCESS

dQ = mRT ln V2/V1

or, dQ/T = (mRT/T) ln V2/V1

or S2 – S1 = mR ln V2/V1 = m(CP – CV) ln V2/V1 = mR ln P1/P2

4. PVy = C; PROCESS

dQ = 0; dS = 0

5. PVn = C; PROCESS

dQ = [(γ – n)/ (γ – 1)] dW

= [(γ – n)/ (γ – 1)] PdV

dQ/T = [(γ – n)/ (γ – 1)] PdV/T

dS = [(γ – n)/ (γ – 1)] mRdV/V

or S2 – S1 = [(γ – n)/ (γ – 1)] mR ln V2/V1

...