If the sum of the distances of a point from two perpendicular lines in a plane is 1, then prove that its locus is a square.
Take the two perpendicular lines as coordinate axes. P(x, y) is a point on the locus ⇔|x| + |y| = 1. This implies that
x + y = 1
x - y = 1
-x + y = 1
-x - y = 1
These lines form a square.