Given that:
Capacity of drum V1 = 0.24m3
Pressure of steam P1 = 11bar
Temperature of steam T1 = 200C
At pressure 11bar from super heated steam table
At 10 bar and T = 200C; =0.2060 m3/kg
At 12 bar and T = 200C; =0.1693 m3/kg
Using linear interpolation:
( – 0.2060)/(0.1693 – 0.206) = (11 – 10)/(12 – 10)
= 0.18765 m3/kg
Quantity of steam = V/ = 0.24/0.18765 = 1.2789 kg
From Saturated steam table
At 11bar; Tsat = 184.09C
2000C > 184.09C
i.e. steam is superheated
If the vessel is cooled until the steam becomes dry saturated, its volume will remain the same but its pressure will change.
From Saturated steam table; corresponding to g = 0.18765, the pressure is 1122.7KPa