First find the support reaction, for that
Convert UDL in to point load, Let reaction at C be RCH and RCV, and at point D be RDV.
RV = 0
RCV + RDV = 1 X 3 + 2RCV + RDV = 5KN ...(1)
Taking moment about point C,
3 X 0.5 + 2 X 5 – RDV X 4 = 0
RDV = 2.875KN ...(2)
From equation (1)
RCV = 2.125KN
Calculation for SFD
Here total 4 section line SF1-1 = 1X1 (inclined line)
At X1 = 0
SFA = 0
At X1 = 1; SFC = 1
SF2-2 = 1X2- RCV (inclined line)
At X2 = 1
SFC = –1.125
At X2 = 3
SFE = 0.875
SF3-3 = 3-RCV (Constant line)
At X3 = 3
SFC = 0.875
At X3 = 5
SFD = 0.875
SF4-4 = 3- RCV - RDV (Constant line)
At X4 = 5
SFD = -2 At
X4 = 7
SFB = –2.
