STEP–1:
First draw a section line which cut the member CE, CD and BD as shown in fig(a) Consider RHS portion of the truss as shown in fig(b). Here Member AB = BC = CD = BE
∑ME = 0
{Moment of force TCE, 1KN is zero}
TCD x ED + TDB cos 45 x ED = 0
TCD = TDB cos 45 TCD = – 1KN
TCD = 1KN (Tensile)
Taking moment about point B
∑MB = 0
{Moment of force TDB, is zero}
– TCD x CB + (1 + TCE cos 45) x CD – TCE sin 45 x (ED + CB) = 0
CB = CD = ED
– 1 + 1 + TCE cos 45 – 2 TCE sin 45 = 0
TCE = 0.
STEP–2:
Draw another section line which cut the member CE and ED Select RHS portion of the truss; There are only two forces on the RHS portion Taking moment about point C We get
TED = 0.
