Consider the function f:[0, ∞) → (- 1/4, ∞), where.
f(x) = x2 - 1/4
Clearly, f is one-one and onto function. So its inverse is exists.
Let its inverse is f-1(x) : [-1/4, ∞) → [0, ∞).
⇒ f-1(x) = √(x + 1/4)
Consequently, we can say that, the two sides of the given equation are inverse to each other.
Thus, the intersection point is the solution of the given equation. f(x) = x.
