The locus of the point equidistant from the points (1, −2, 3) and (−3, 4, 2) is
(A) 8x - 12y + 2z +15 = 0
(B) 8x + 12y - 2z +15 = 0
(C) 8x - 12y - 2z +15 = 0
(D) 8x - 12y + 2z - 15 = 0
Correct option is (a) 8x - 12y + 2z + 15 = 0
Explanation :
Let A = (1, −2, 3) and B = (−3, 4, 2). P(x, y, z) is a point on the locus
PA = PB. So
(PA)2 = PB)2
(x - 1)2 + (y + 2)2 + (z - 3)2 = (x + 3)2 + (y - 4)2 + (z - 2)2
8x - 12y + 2z + 15 = 0
