When 1 g liquid naphthalene (C10H8) solidifies.149 joules of heat is evolved. Calculate the enthalpy of fusion of naphthalene.

Question 1

Question 2

Molar mass of naphthalene (C10H8 ) = 128 g mol–1 When 1 g of liquid naphthalene solidified, heat evolved = 149 joules

When 1 mole, i.e., 128 g of naphthalene solidifies, heat evolved = 149 joules.

When 1 mole, i.e., 128 g of naphthalene solidifies, heat evolved = 149 × 128 joules = 19072 joules

Since fusion is reverse of solidification, therefore, heat absorbed for fusion of one mole of naphthalene = 19072 joules.

i.e., Enthalpy of fusion (Δfus H) = + 19072 joules/mole

kratos · Answer 1 · 2020-05-16T00:59:47+0000

Molar mass of naphthalene (C10H8 ) = 128 g mol–1 When 1 g of liquid naphthalene solidified, heat evolved = 149 joules

When 1 mole, i.e., 128 g of naphthalene solidifies, heat evolved = 149 joules.

When 1 mole, i.e., 128 g of naphthalene solidifies, heat evolved = 149 × 128 joules = 19072 joules

Since fusion is reverse of solidification, therefore, heat absorbed for fusion of one mole of naphthalene = 19072 joules.

i.e., Enthalpy of fusion (Δfus H) = + 19072 joules/mole

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