Question

4 mole of an ideal gas having γ = 1.67 are mixed with 2 mole of another ideal gas having γ = 1.4. Find the equivalent value of γ for the mixture.

Answer 1

The problem can be solved using the following two equations,

γ =Cp/CV and C'p = CV +R

C’V = Molar heat capacity of the first gas,

C’V = Molar heat capacity of the second gas,

CV = Molar heat capacity of the mixture

CV = Molar heat capacity of the first gas,

CV = Molar heat capacity of the second gas,

CV = Molar heat capacity of the mixture

and similar symbols for other quantities. Then,

Suppose the temperature of the mixture is increased by dT. The increase in the internal energy of the first gas = n1Cv C dT.

The increase in internal energy of the second Gas = n2CV and the increase in internal energy of the