+3 votes
in JEE by kratos

CH4(g) +Cl2(g) →CH3Cl (g) +HCl(g).has ∆H =-25 kCal

From the given data, what is the bond enthalpy of Cl-Cl bond

(A) 70 kCal

(B) 80 kCal

(C) 67.75 kCal

(D) 57.75 kCal

1 Answer

+2 votes
by kratos
 
Best answer

Correct option (D) 57.75 kCal

Explanation:

CH4 + Cl2 → CH3Cl + HCl

∆H = -25

–25 = 4 × C – H + 4Cl

– Cl – 3 × CH – 1C – Cl – 1 H – Cl

–25 = 4x + y – 3x – 84 – 103

y – x = 162

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