(i) Let f(x) = sin(π[x])
Since [x] provides us integer, so f(x) = 0
It is continuous and differentiable everywhere
(ii) Let f(x) = sin(π(x – [x]))
= sin (π{x})
As we know that, {x} is discontinuous at every integral points, so f(x) is disc at all integers
Thus f(x) is non-differentiable at x = – 1 and 1.