Find the equations of the hyperbola whose foci are (±5, 0) the transverse axis is of length 8.
Foci are *(±5,0) ∴ ae = 5
Length of transverse axis = 2a = 8, a = 4
e = 5/4
b2 = a2 (e2 – 1) = 16(25/6 - 1) = 9
Equation of the hyperbola is x2/16 – y2/9 = 1
9x2 – 16y2 = 144.
