Question

If y = c1ex + c2e–x, then prove that d2y/dx2 – y = 0.

Answer 1

We have y = c1ex + c2e–x

⇒ dy/dx = c1ex – c2e–x

⇒ d2y/dx2 = c1ex + c2e–x = y

⇒ d2y/dx2 – y = 0.