The two springs are identical, with unstretched length 0.4 m. When the 50-kg mass is suspended at B, the length of each spring increases to 0.6 m.

Question 1

The two springs are identical, with unstretched length 0.4 m. When the 50-kg mass is suspended at B, the length of each spring increases to 0.6 m. What is the spring constant k?

Question 2

F = k (0.6 m - 0.4 m)

∑ Fy : 2F sin 60° - 490.5 N = 0

k = 1416 N/m.

kratos · Answer 1 · 2020-03-29T12:25:33+0000

F = k (0.6 m - 0.4 m)

∑ Fy : 2F sin 60° - 490.5 N = 0

k = 1416 N/m.

The two springs are identical, with unstretched length 0.4 m. When the 50-kg mass is suspended at B, the length of each spring increases to 0.6 m.

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The two springs are identical, with unstretched length 0.4 m. When the 50-kg mass is suspended at B, the length of each spring increases to 0.6 m.

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1 Answer

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