Find the least value of f(x) = 2log10 x – logx (0.01), x > 1
We have f(x) = 2log10 x – logx (0.01), x > 1
⇒ f(x) = 2 log10 x – logx(10)– 2
⇒ f(x) = 2 log10 x + 2 logx(10)
⇒ f(x) = 2 (log10x + logx (10))
⇒ f(x) = 2 (log10x + logx (10)) ≥ 4
Hence, the min value of f(x) is 4.
