+3 votes
in Chemistry by kratos

a)0.29 L

b)0.28 L

c)0.20 L

d)0.3 L

1 Answer

+6 votes
by kratos
 
Best answer

Solution:

  • Electrode equations:
+ (-) cathode **2H+ + 2 e- ==> H2**or **4H+ + 4e-**==>**2H2** for molar electron comparison
+ (+) anode **4OH- -2e- ==> 2H2O(l) + O2**
  • Quantity of electricity in Coulombs = current in A x time in seconds
  • Q = I x t = 1 x 20 x 60 = 1200 C, now 1 mole of electrons = 96500 C
  • so of electrons = 1200 / 96500 = 0.012435
  • it takes 4 ***** of electrons to form 1 mole of oxygen gas
  • therefore ***** of oxygen formed = 0.012435 / 4 = 0.0031
  • 1 mole of gas = 24000 cm3, therefore volume of gas = 0.0031 x 24000 = 74.4 cm3 of O2
  • volume of gas = 0.0744 L of O2
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