+2 votes
in Class 12 by kratos

Two bulbs are rated (P1, V) and (P2, V). If they are connected (i) in series and (ii) in parallel across a supply V, find the power dissipated in the two combinations in terms of P1 and P2.

1 Answer

+3 votes
by kratos
 
Best answer

Electric power of a circuit is defined as the rate at which the work is done by the source of emf in maintaining the current in electric circuit. Electric power is given as

where V is the potential difference, I is the current, and R is the resistance.

(i) When two bulbs rated (P1, V) and (P2,V) are connected in series:

The current is the same through each bulb. If R1 and R2 are resistances of two bulbs, then the effective resistance of the circuit is

R = R1 + R2

Using the relation

we have

Given: V1 = V2 = V. Therefore,

Thus, the effective power when two bulbs are connected in series is

(ii) When two bulbs rated (P1, V) and (P2,V) are connected in parallel

Using the relation

we get

Given: V1 = V2 = V. Therefore,

Thus, the effective power when two bulbs are connected in parallel is

P = P1 + P2.

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