+3 votes
in Class 11 by kratos

A stone of mass m, tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity.) The length of the string is reduced gradually, keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T = Arn , where A is a constant, r is the instantaneous radius of the circle, and n is

(a) 1

(b) -1

(c) -2

(d) -3

1 Answer

+1 vote
by kratos
 
Best answer

Correct Answer is: (d) -3

L = mvr = constant.

T = mv2 / r = m/r. L/m2r2 = L/m r-3 .

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