If L = ∫(log(1 + x)/(1 + x2)) dx for x ∈ [0,1] and M = ∫log(1 + tanθ) dθ for θ ∈ [0,π/4] such that L + M = (π/A)log B, find the value of A + B + 3.
Let
Let x = tan θ
dx = sec2 θ dθ
and Let
So, A = 4 and B = 2
Hence, the value of
A + B + 3 = 9