Question

If f(x) = ∫e– t^2 dt for t ∈ [x2,x2 + 1], f(x) increases in

(a) (– 2,2)

(b) no value in x

(c) (0,∞)

(d) (–∞,0)

Answer 1

Answer is (c) (0, ∞)

Given

Clearly f(x) increases in (0,∞).