Out of three given numbers, the first number is twice the second and thrice the third. If the average of the three numbers is 154, what is the difference between the first and the third number?
(a) 126 (b) 42 (c) 166 (d) 52 (e) of these
(e) Let the first number be = 6x Second number = 3x and the third number = 2x According to the question, 6x + 3x + 2x = 154 × 3 or, 11x = 154 × 3
Required difference = 6x – 2x = 4x = 4 × 42 = 168
