Correct Answer is: (d) 1500 J/°C
Rate of loss of heat ∝ difference in temperature with the surroundings.
At 50°C, dQ/dt = k(50 - 20) = 10, where k = constant
uf05c k = 1/3
At an average temperature of 35°C, dQ/dt = 1/3 (35 - 20) J/ = 5 J/.
Heat lost in 1 minute = dQ/dt x 60 J = 5 x 60 J = 300 J = Q.
Fall in temperature = 0.2°C Δθ.
Q = cΔθ.
Heat capacity = c Q/Δθ = 300 J/0.2°C.