Correct Answer is: (a) Imax = 0.64 I0 , (c) Imax /Imin = 16
Let a = initial amplitude due to S1 and S2 each.
I0 = k(4a2), where k is a constant.
After reduction of power of S1, amplitude due to S1 = 0.6a.
Due to superposition, amax = a + 0.6a = 1.6a, and
amin = a - 0.6a = 0.4a
Imax/Imin = (amax/amin)2 = (1.6a/0.4a) = 16.