+2 votes
in Class 12 by kratos

Using integration find the area of the triangular region whose sides have equations y = 2x +1, y = 3x +1 and x = 4.

1 Answer

+1 vote
by kratos
 
Best answer

The given lines are
y = 2x + 1 …(i)
y = 3x + 1 …(ii)
x = 4 …(iii)

For intersection point of (i) and (iii)
y = 2x4 + 1 = 9
Coordinates of intersecting point of (i) and (iii) is (4, 9)
For intersection point of (ii) and (iii)
y = 3x4 + 1 = 13
i.e., Coordinates of intersection point of (ii) and (iii) is (4, 13)
For intersection point of (i) and (ii)
2x + 1 = 3x + 1 => x = 0
y = 1
i.e., Coordinates of intersection point of (i) and (ii) is (0, 1).
Shaded region is required triangular region.
Required Area = Area of trapezium OABD - Area of trapezium OACD

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