If y = f((2x - 1)/(x2 + 1)) and f'(x) = sinx2, then dy/dx is
(A) cosx2.f'(x)
(B) - cosx2.f'(x)
(C) 2(1 + x - x2)/(x2 + 1)2 sin((2x - 1)/(x2 + 1))2
(D) of these
Answer is (C) 2(1 + x - x2)/(x2 + 1)2 sin((2x - 1)/(x2 + 1))2