+2 votes
in JEE by kratos

The equation of a normal to the curve, siny = xsin(π/3 + y) at x = 0, is

(A) 2x + √3y = 0

(B) 2y - √3x = 0

(C) 2y + √3x = 0

(D) 2x - √3y = 0

1 Answer

+1 vote
by kratos
 
Best answer

Answer is (A) 2x + √3y = 0

Given value curve is

Therefore, Equation of normal at (0, 0) is

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