The area of the triangle formed by the coordinate axes and a tangent to the curve xy = a2 at the point (x1, y1) on it is
(A) a2x1/y1
(B) a2y1/x1
(C) 2a2
(D) 4a2
Answer is (C) 2a2
We have
y = a2/x
Therefore,
or x = 2x1
Therefore, the point on x-axis is (2x1, 0). Now, the tangent meets y-axis where x = 0. Since