The normal to the curves x = a(1 + cosθ) and y = asinθ at angle θ always passes through the fixed point
(A) (a, a)
(B) (0, a)
(C) (0, 0)
(D) (a, 0)
Answer is (D) (a, 0)
The slope of the normal is
Now, the equation of normal at θ is
y - asinθ = tanθ[x - a(1 + cosθ)]
Clearly, this line passes through (a, 0).