Answer is (B), (C)
See Fig.
f(x) = ax3 + bx2 + cx + d
Now, f(x) is odd. Therefore,
f(−x) = − f(x)
⇒ −ax3 − bx2 − cx − d = −ax3 + bx2 − cx + d
It gives b = 0 = d
f(x) = ax3 + cx = x (ax2 + c)
Therefore,
f′(x) = 3ax2 + c = 0
Only when x2 = − 3 c a is positive.
Therefore, c and a are of different signs.
Let − c/a = k.