+3 votes
in JEE by kratos

Evaluate ∫(x3m + x2m + xm) .(2x2m + 3xm + 6)1/mdx. (x > 0)

1 Answer

+5 votes
by kratos
 
Best answer

I = ∫(x3m - 1 + x2m - 1 + xm - 1) .(2x3m + 3x2m + 6m)1/mdx

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