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Evaluate ∫(sin2x/(a^2sin^2x + b^2cos^2x))dx.
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Apr 5, 2019
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JEE
by
kratos
Evaluate ∫(sin2x/(a2sin2x + b2cos2x))dx.
jee
indefinite integration
jee mains
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+4
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answered
Feb 3, 2020
by
kratos
Best answer
I = ∫(sin2x/(a2sin2x + b2cos2x))dx
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