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Evaluate ∫(((x^3 + 8)(x - 1))/(x^2 - 2x + 4))dx.
+3
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asked
Mar 24, 2019
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JEE
by
kratos
Evaluate ∫(((x3 + 8)(x - 1))/(x2 - 2x + 4))dx.
jee
indefinite integration
jee mains
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+5
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answered
Aug 21, 2020
by
kratos
Best answer
= x3/3 + x2/2 - 2x + c
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