Using differentials, find the approximate value of (0.999)1/10, upto three places of decimal.
Let y = f(x) = x1/10 and f(1) = (1)1/10 = 1
when a = 1, f(a) = f(1) = 1
we have to find out
f(0.999) = f(1 - 0.001)
δα = - 0.001